The net requirement of assimilatory power for the formation of 6 hexose molecules in maize plant is

Options

A. 72 ATP , 48 NADPH
B. 90 ATP, 60 NADPH
C. 108 ATP , 72 NADPH
D. 180 ATP , 72 NADPH

Answer

To determine the net requirement of assimilatory power for the formation of 6 hexose molecules in maize (a C4 plant), we follow these steps:

### Step-by-Step Solution:

1. **Identify the Type of Plant**:
- Maize is a C4 plant. C4 plants have specific requirements for ATP and NADPH during photosynthesis.

2. **Determine the Requirements for One Hexose Molecule**:
- For the formation of one hexose molecule (which is glucose), C4 plants require:
- 30 molecules of ATP
- 12 molecules of NADPH

3. **Calculate the Requirements for Six Hexose Molecules**:
- Since we need to form 6 hexose molecules, we multiply the requirements for one hexose molecule by 6:
- For ATP:
\[ 30 \text{ ATP} \times 6 = 180 \text{ ATP} \]
- For NADPH:
\[ 12 \text{ NADPH} \times 6 = 72 \text{ NADPH} \]

4. **Summarize the Total Requirements**:
- Therefore, the total requirements for the formation of 6 hexose molecules in maize are:
- **180 molecules of ATP**
- **72 molecules of NADPH**

5. **Select the Correct Option**:
- Based on the calculations, the correct answer is the option that states 180 ATP and 72 NADPH.

### Final Answer:
The net requirement of assimilatory power for the formation of 6 hexose molecules in maize plant is **180 ATP and 72 NADPH**.

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