Calculate molarity of the resultant solution obtained by mixing 1 M and 2 .5 liter NaON solution and 0.5 M 3 liter NaOH solution .

Options

A. 0.50 M
B. 0.73 M
C. 0.80 M
D. 1.0 M

Answer

To calculate the molarity of the resultant solution obtained by mixing 1 M NaOH solution (2.5 liters) and 0.5 M NaOH solution (3 liters), we can follow these steps:

### Step 1: Calculate the moles of NaOH in each solution.

1. For the first solution:
- Molarity (M1) = 1 M
- Volume (V1) = 2.5 L
- Moles of NaOH (n1) = M1 × V1 = 1 M × 2.5 L = 2.5 moles

2. For the second solution:
- Molarity (M2) = 0.5 M
- Volume (V2) = 3 L
- Moles of NaOH (n2) = M2 × V2 = 0.5 M × 3 L = 1.5 moles

### Step 2: Calculate the total moles of NaOH.

- Total moles of NaOH (n_total) = n1 + n2 = 2.5 moles + 1.5 moles = 4 moles

### Step 3: Calculate the total volume of the resultant solution.

- Total volume (V_total) = V1 + V2 = 2.5 L + 3 L = 5.5 L

### Step 4: Calculate the molarity of the resultant solution.

- Molarity (M3) = Total moles of NaOH / Total volume = n_total / V_total = 4 moles / 5.5 L = 0.727 M (approximately 0.73 M)

### Final Answer:
The molarity of the resultant solution is approximately **0.73 M**.

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