Which one of following is a wrong statement?

Options

A. The uncertainty principle is `DeltaExxDeltatgeh//4pi`
B. Half filled and fully filled orbitals have greater stability due to greater exchange energy , greater symmetry and more balanced arrangement.
C. The energy of 2s orbital is less than the energy of 2p orbital in case of Hydrogen like atoms.
D. De - Broglie's wavelength is given by `lamda=h/(mv)` , where m = mass of the particle , v= group velocity of the particle.

Answer

To determine which statement is wrong, we will analyze each of the four statements provided in the question.

### Step-by-Step Solution:

1. **Evaluate Statement 1**:
- The statement claims that the uncertainty principle is represented by the equation \( \Delta E \cdot \Delta T \geq \frac{h}{4\pi} \).
- This is a correct representation of the uncertainty principle. The uncertainty principle states that the product of the uncertainties in energy (\( \Delta E \)) and time (\( \Delta T \)) is indeed greater than or equal to \( \frac{h}{4\pi} \).

**Hint**: Recall the basic principles of quantum mechanics and the uncertainty principle.

2. **Evaluate Statement 2**:
- The statement mentions that half-filled and fully-filled orbitals have greater stability due to greater exchange energy, greater symmetry, and more balanced arrangement.
- This statement is also correct. Half-filled and fully-filled orbitals exhibit greater stability due to increased exchange energy and symmetry, as per Hund's rule.

**Hint**: Consider the concepts of electron configuration and stability in atomic orbitals.

3. **Evaluate Statement 3**:
- The statement asserts that the energy of the 2s orbital is less than the energy of the 2p orbital in hydrogen-like atoms.
- This statement is incorrect. In hydrogen-like atoms, the 2s and 2p orbitals have the same energy. Therefore, this statement is wrong.

**Hint**: Remember the energy levels of orbitals in hydrogen-like atoms and how they are affected by the principal quantum number.

4. **Evaluate Statement 4**:
- The statement states that the de Broglie wavelength is given by \( \lambda = \frac{h}{mv} \).
- This is a correct expression for the de Broglie wavelength, where \( h \) is Planck's constant, \( m \) is the mass of the particle, and \( v \) is its velocity.

**Hint**: Review the de Broglie hypothesis and the relationship between wavelength and momentum.

### Conclusion:
After evaluating all four statements, we find that Statement 3 is the only incorrect statement. Thus, the answer to the question is:

**Answer**: Statement 3 is the wrong statement.