In given reaction [X] and [Y] respectively are `CH_3-overset(O)overset(||)C-O-underset(CH_3)underset(|)overset(CH_3)overset(|)C-CH_3overset(Na//C_2H_5OH)rarr(X)+(Y)`

Options

A. `CH_3-CH_2-OH and CH_3-underset(CH_3)underset(|)overset(CH_3)overset(|)C-OH`
B. `CH_3-CH_2-OH and CH_3-underset(CH_3) underset(|)C-CH_2`
C. `CH_2=CH_2 and CH_3-underset(CH_3)underset(|)overset(CH_3)overset(|)C-OH`
D. `CH_3-CH_2-underset(CH_3)underset(|)overset(CH_3)overset(|)O-C-CH_3`

Answer

To solve the problem, we need to analyze the reaction given and determine the products X and Y when the compound reacts with sodium in ethanol (Na/C2H5OH).

### Step-by-Step Solution:

1. **Identify the Structure**:
The compound given is a tertiary alcohol with the structure:
\[ CH_3-C(=O)-O-CH(CH_3)_2 \]
This is a tertiary butyl ester.

2. **Reaction with Sodium and Ethanol**:
When this ester reacts with sodium in ethanol, sodium acts as a reducing agent. The sodium donates an electron to the carbonyl carbon, leading to the formation of a radical intermediate.

3. **Formation of Products**:
The reaction proceeds as follows:
- The carbonyl group (C=O) gets reduced to an alcohol (C-OH).
- The ester bond breaks, leading to the formation of two products: a tertiary alcohol and an aldehyde.

4. **Identify Product X**:
The first product (X) formed is the tertiary alcohol from the ester, which is tert-butyl alcohol:
\[ (CH_3)_3COH \]

5. **Identify Product Y**:
The second product (Y) is the aldehyde that results from the reduction of the carbonyl group. This would be:
\[ CH_3CHO \]
(which is acetaldehyde).

6. **Final Products**:
Thus, the products of the reaction are:
- Product X: tert-butyl alcohol
- Product Y: acetaldehyde

### Conclusion:
The final answer for the products X and Y is:
- X = tert-butyl alcohol
- Y = acetaldehyde