How many amino acids will be coded by following given or more than one cytosine represent the intron?
AUG CCC CAC CAC UUA UAU AUA GGC GAC AAA GCG UUU CAU UAA

Options

A. 7
B. 8
C. 10
D. 11

Answer

To determine how many amino acids are coded by the given mRNA sequence, we need to follow these steps:

### Step 1: Identify the mRNA sequence
The given mRNA sequence is:
```
AUG CCC CAC CAC UUA UAU AUA GGC GAC AAA GCG UUU CAU UAA
```

### Step 2: Break down the mRNA into codons
Codons are groups of three nucleotides. We will divide the sequence into codons:
```
AUG | CCC | CAC | CAC | UUA | UAU | AUA | GGC | GAC | AAA | GCG | UUU | CAU | UAA
```

### Step 3: Count the number of cytosines (C)
Next, we will count how many cytosines (C) are present in the codons:
- AUG: 0 C
- CCC: 3 C
- CAC: 1 C
- CAC: 1 C
- UUA: 0 C
- UAU: 0 C
- AUA: 0 C
- GGC: 1 C
- GAC: 1 C
- AAA: 0 C
- GCG: 1 C
- UUU: 0 C
- CAU: 0 C
- UAA: 0 C

Now, let's tally the total number of cytosines:
- CCC: 3
- CAC: 1 + 1 = 2
- GGC: 1
- GAC: 1
- GCG: 1

Total C = 3 + 2 + 1 + 1 + 1 = 8

### Step 4: Determine the number of amino acids coded
Each codon codes for one amino acid. The stop codon (UAA) does not code for an amino acid. Therefore, we will count the number of codons that code for amino acids:
- Total codons = 14
- Stop codon = 1 (UAA)

Thus, the number of amino acids coded = Total codons - Stop codon = 14 - 1 = 13.

### Final Answer
The number of amino acids coded by the given mRNA sequence is **13**.

---