The products obtained form the following chemical reactions are respectively
(i) `underset(("hot and conc."))(NaOH)+Cl_2rarr`
(ii) ` underset(("excess"))(XeF_6)+H_2Orarr`

Options

A. `NaOH and XeO_3`
B. `HClO_3 and XeO_2F_2`
C. `NaClO_3 and XeOF_4`
D. none of these

Answer

To determine the products of the given chemical reactions, we will analyze each reaction step by step.

### Reaction (i):
**Reactants:** `NaOH (hot and concentrated) + Cl2`

1. **Identify the conditions:** The reaction involves hot and concentrated sodium hydroxide (NaOH) with chlorine gas (Cl2).

2. **Understand the reaction:** In this scenario, when NaOH is hot and concentrated, it reacts with Cl2 to undergo a disproportionation reaction.

3. **Products formation:** The products formed from this reaction are sodium chloride (NaCl) and sodium chlorate (NaClO3).

4. **Balanced equation:** The balanced chemical equation for this reaction is:
\[ 6 \text{NaOH} + 3 \text{Cl}_2 \rightarrow 5 \text{NaCl} + \text{NaClO}_3 + 3 \text{H}_2\text{O} \]

### Reaction (ii):
**Reactants:** `XeF6 (excess) + H2O`

1. **Identify the conditions:** The reaction involves xenon hexafluoride (XeF6) in excess with water (H2O).

2. **Understand the reaction:** When XeF6 reacts with water, it undergoes hydrolysis. The presence of excess water indicates that the reaction will go to completion.

3. **Products formation:** The products formed from this hydrolysis reaction are xenon tetrafluoride (XeOF4) and hydrofluoric acid (HF).

4. **Balanced equation:** The balanced chemical equation for this reaction is:
\[ \text{XeF}_6 + 2 \text{H}_2\text{O} \rightarrow \text{XeOF}_4 + 2 \text{HF} \]

### Final Products:
- From reaction (i): **NaCl and NaClO3**
- From reaction (ii): **XeOF4 and HF**

### Summary of Products:
1. From `NaOH (hot and concentrated) + Cl2`: **NaCl and NaClO3**
2. From `XeF6 (excess) + H2O`: **XeOF4 and HF**