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Two masses `m_(1)` and `m_(2)` are suspended together by a massless spring of constant K. When the masses are in equilibrium, `m_(1)` is removed without disturbing the system. Then the angular frequency of oscillation of `m_(2)` is -

A

`omega=sqrt(k/m_2)`

B

`omega=sqrt(k/(m_2-m_1))`

C

Can't be determined

D

None of these

Text Solution

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The correct Answer is:
A
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