Product formed in the following reaction is `CH_3CH_2CH(OH)CH_3overset(H_2SO_4)rarr`

Options

A. `CH_3CH=CHCH_3` predominates
B. `CH_2=CHCH_2CH_3` predominates
C. Both are formed in equal amounts
D. The amount of production depends on the nature of catalyst

Answer

To solve the question regarding the product formed from the reaction of 2-butanol with sulfuric acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant is 2-butanol, which has the structure CH₃CH₂CHOHCH₃.

2. **Reaction with Sulfuric Acid**: When 2-butanol reacts with sulfuric acid (H₂SO₄), it undergoes protonation. The hydroxyl (-OH) group of 2-butanol can be protonated by H⁺ from sulfuric acid, forming a better leaving group (water).

3. **Formation of Carbocation**: The protonation of the alcohol leads to the formation of a carbocation. The reaction can be represented as:
\[ CH₃CH₂CHOHCH₃ + H^+ \rightarrow CH₃CH₂C^+(OH)CH₃ \]
Here, the oxygen atom donates its lone pair to H⁺, resulting in a positively charged carbocation.

4. **Carbocation Stability**: The carbocation formed is a secondary carbocation (2°), which is relatively stable.

5. **Elimination Reaction**: The next step involves the elimination of a proton (H⁺) from a carbon adjacent to the carbocation. According to Zaitsev's rule, the hydrogen will be removed from the carbon that has fewer hydrogens to form a double bond:
\[ CH₃CH₂C^+(OH)CH₃ \rightarrow CH₃CH=CHCH₃ + H₂O \]

6. **Final Product**: The major product of this elimination reaction is 2-butene (CH₃CH=CHCH₃), which is the result of the dehydration of 2-butanol.

### Conclusion:
The product formed in the reaction of 2-butanol with sulfuric acid is **2-butene (CH₃CH=CHCH₃)**.

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