An AC voltage source of variable angular...

An AC voltage source of variable angular frequency `(omega)` and fixed amplitude `V_(0)` is connected in series with a capacitance C and an electric bulb of resistance R (inductance zero). When `(omega)` is increased

The bulb glows dimmer

The bulb glows brighter

Total impedance of the circuit is unchanged

Total impedance of the circuit increases

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A box P and a coil Q are connected in series with an AC source of variable frequency. The emf of the source is constant at 10 V . Box P contains a capacitance of 1 mu F in series with a resistance of 32 Omega . Coil Q has a self-inductance 4.9 mH and a resistance of 68 Omega in series. The frequency is adjusted to that the maximum current flows in P and Q . At this frequency (a) The impedance of P is 77 Omega (b) The impedance of Q is 85 Omega (c ) Voltage across P is 7.7 V (d) Voltage across Q is 9.7 V

A series LCR circuit having resistance R, capacitance C and inductance L has a voltage source of angular frequency omega and voltage V_(in). Output voltage (V_(out)) is taken as voltage across the resistor and inductor combined. (a) Find eta=(V_(out))/V_("in") (b) Find eta in the limit of large omega(omegagtgt(1)/(RC),(1)/(sqrt(LC)),(R)/(L)) (C )Find eta in the limit of small omega(omegagtgt(1)/(RC),(1)/(sqrt(LC)),(R)/(L))

A box P and a coil Q are connected in series with an AC source of variable frequency.The EMF of source is constant at 10 V .Box P contains a capacitance of 1 muF in series with a resistance of 32 Omega .Coil Q has a self inductance 4.9 mH and a resistance of 68 Omega .The frequency is adjusted so that the maximum current flows in P and Q .Find the impedance of P and Q at this frequency.Also find the voltage across P and Q respectively.

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