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For the weak electrolyte , their degree ...

For the weak electrolyte , their degree of dissociation increase

A

One increasing dilution

B

On decreasing diluation

C

On increasing pressure

D

None of these

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To solve the question regarding the degree of dissociation of a weak electrolyte, we will follow these steps: ### Step 1: Understanding the Weak Electrolyte A weak electrolyte, such as HA, partially dissociates in solution. The dissociation can be represented as: \[ HA \rightleftharpoons H^+ + A^- \] ### Step 2: Setting Up the Equilibrium Expression Let the initial concentration of the weak electrolyte HA be \( C \). If \( x \) is the amount that dissociates, then at equilibrium: - Concentration of \( HA \) = \( C - x \) - Concentration of \( H^+ \) = \( x \) - Concentration of \( A^- \) = \( x \) ### Step 3: Defining Degree of Dissociation The degree of dissociation \( \alpha \) is defined as the fraction of the original substance that has dissociated: \[ \alpha = \frac{x}{C} \] ### Step 4: Writing the Equilibrium Constant Expression The equilibrium constant \( K_a \) for the dissociation of the weak electrolyte can be expressed as: \[ K_a = \frac{[H^+][A^-]}{[HA]} = \frac{x \cdot x}{C - x} = \frac{x^2}{C - x} \] ### Step 5: Applying the Assumption for Weak Electrolytes For weak electrolytes, \( x \) (the amount dissociated) is usually much smaller than \( C \). Therefore, we can approximate: \[ C - x \approx C \] This simplifies our expression for \( K_a \): \[ K_a \approx \frac{x^2}{C} \] ### Step 6: Relating Degree of Dissociation to Concentration Substituting \( x = C \alpha \) into the equation gives: \[ K_a \approx \frac{(C \alpha)^2}{C} = C \alpha^2 \] ### Step 7: Understanding the Effect of Dilution According to the principle of dilution (L'Hospital's dilution law), as the concentration \( C \) decreases (i.e., when we dilute the solution), \( K_a \) remains constant. Therefore, if \( C \) decreases, \( \alpha \) must increase to keep \( K_a \) constant: \[ K_a = C \alpha^2 \] This implies: \[ \alpha \propto \frac{1}{\sqrt{C}} \] Thus, as the concentration decreases (or volume increases), the degree of dissociation \( \alpha \) increases. ### Conclusion The degree of dissociation of a weak electrolyte increases with dilution. ---
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