In the series of reaction X and Y are respectively are `C_6H_5NH_2overset(NaNO_2//HCl)rarrXoverset(HNO_2)rarrY+N_2+HCl`

Options

A. `C_6H_5-N=N-C_6H_5,C_6H_5N_2^o+Cl^(Theta)`
B. `C_6H_5N_2^o+Cl^(Theta),C_6H_5-N=N-C_6H_5,`
C. `C_6H_5N_2^o+Cl^(Theta),C_6H_5NO_2`
D. `C_6H_5NO_2,C_6H_6`

Answer

To solve the given problem, we need to analyze the series of reactions involving aniline (C6H5NH2) and the products formed through the reactions with nitrous acid (HNO2) and hydrochloric acid (HCl).

### Step-by-Step Solution:

1. **Identify the Starting Material:**
The starting material is aniline, which has the molecular formula C6H5NH2.

2. **First Reaction with NaNO2 and HCl:**
When aniline reacts with sodium nitrite (NaNO2) in the presence of hydrochloric acid (HCl), it forms a diazonium salt. The reaction can be represented as:
\[ C6H5NH2 + NaNO2 + HCl \rightarrow C6H5N2^+Cl^- + 2H2O \]
Here, the aniline is converted into the diazonium salt (C6H5N2^+Cl^-), which is our compound X.

3. **Formation of Compound Y:**
The diazonium salt (X) then reacts with nitrous acid (HNO2). The nitrous acid can be generated in situ from sodium nitrite and hydrochloric acid. The reaction is as follows:
\[ C6H5N2^+Cl^- + HNO2 \rightarrow C6H5OH + N2 + HCl \]
In this reaction, the diazonium salt decomposes to form phenol (C6H5OH), nitrogen gas (N2), and hydrochloric acid (HCl). The phenol is our compound Y.

4. **Final Products:**
After the reactions, we have:
- Compound X: C6H5N2^+Cl^-
- Compound Y: C6H5OH

### Summary of the Reaction:
- Starting Material: C6H5NH2 (Aniline)
- Intermediate (X): C6H5N2^+Cl^- (Diazonium salt)
- Final Product (Y): C6H5OH (Phenol) + N2 + HCl

### Conclusion:
The correct identification of compounds X and Y from the reactions is:
- X = C6H5N2^+Cl^-
- Y = C6H5OH