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Equimolar solution of HF, HCOOH and HCN ...

Equimolar solution of HF, HCOOH and HCN at 298 K have the values of Ka as `6.8xx10^(-4), 1.8xx10^(-4)` and `4.8xx10^(-9)` respectively, what will be the order of their acidic strength ?

A

`HF gt HCN gt HCOOH`

B

`HF gt HCOOH gt HCN`

C

`HCN gt HF gt HCOOH`

D

`HCOOH gt HCN gt HF`

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The correct Answer is:
B
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Equimoler solulition of HF, HCOOH and HCN at 298 K have the values of Ka as 6.8xx10^(-4), 1.8xx10^(-4) and 4.8xx10^(-9) respectively, what will be the order of their acidic strength ?

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