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The binding energy per nucleon of .3^7L...

The binding energy per nucleon of `._3^7Li` and `._2^4He` nuclei are 5.60 MeV and 7.06 MeV respectively. In the nuclear reaction `._3^7Li + ._1^1H to 2._2^4He + Q` , the value of energy Q released is

A

19.6 MeV

B

`-2.4 MeV`

C

8.4 MeV

D

17.3 MeV

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The correct Answer is:
D
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NTA MOCK TESTS-NTA NEET SET 67-PHYSICS
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