In the `beta^+` decay process , the following changes take place inside the nucleus

Options

A. `._Z^AXrarr._(Z-1)^AY+e^(+)+gamma`
B. `._Z^AXrarr._(Z+1)^AY+e^(-)+bargamma`
C. `._Z^AXrarr._(Z)^AY+e^(-)+gamma`
D. `._Z^AXrarr._(Z)^AY+e^(-)+bargamma`

Answer

To solve the question regarding the changes that occur inside the nucleus during the beta plus (β+) decay process, we can follow these steps:

### Step 1: Understanding Beta Plus Decay
In beta plus decay, a proton in the nucleus is transformed into a neutron. This process involves the emission of a positron (e+) and a neutrino (ν).

### Step 2: Identify the Initial Nucleus
Let's consider an example nucleus, Carbon-10 (¹⁰C), which has 6 protons and 4 neutrons. The atomic number (Z) is 6, and the mass number (A) is 10.

### Step 3: Transformation During Beta Plus Decay
During beta plus decay:
- One proton (p) is converted into one neutron (n).
- The atomic number decreases by 1 (from 6 to 5), while the mass number remains unchanged (still 10).
- The resulting nucleus is Boron-10 (¹⁰B), which has 5 protons and 5 neutrons.

### Step 4: Emission of Particles
Along with the transformation of a proton into a neutron, a positron and a neutrino are emitted:
- Positron (e+) is emitted as a result of the decay.
- Neutrino (ν) is also emitted.

### Step 5: Writing the Decay Equation
The beta plus decay can be represented as follows:
\[ {}^{10}_{6}\text{C} \rightarrow {}^{10}_{5}\text{B} + e^+ + \nu \]

### Step 6: Conclusion
In summary, during beta plus decay:
- The atomic number decreases by 1.
- The mass number remains unchanged.
- A positron and a neutrino are emitted.

### Final Answer
The correct changes that take place inside the nucleus during beta plus decay are:
- A proton is converted into a neutron.
- A positron and a neutrino are emitted.
- The atomic number decreases by 1 while the mass number remains the same.