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What is the pl of glycine ? The structur...

What is the pl of glycine ? The structure and pKa values are shown below.
`H-underset(pKa=9.60)underset(darr)underset(o+)underset(NH_3)underset(|)overset(H)overset(|)C-COOHlarrpKa=2.34`

A

2.26

B

5.97

C

3.63

D

11.94

Text Solution

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The correct Answer is:
To find the isoelectric point (pI) of glycine, we will use the given pKa values for the carboxyl group (pKa1 = 2.34) and the ammonium group (pKa2 = 9.60). The pI is calculated as the average of these two pKa values. Here’s a step-by-step solution: ### Step 1: Identify the pKa values - The pKa of the carboxylic acid group (COOH) is 2.34. - The pKa of the ammonium ion (NH3+) is 9.60. ### Step 2: Use the formula for pI The formula for calculating the isoelectric point (pI) is: \[ \text{pI} = \frac{\text{pKa1} + \text{pKa2}}{2} \] ### Step 3: Substitute the pKa values into the formula Substituting the identified pKa values into the formula: \[ \text{pI} = \frac{2.34 + 9.60}{2} \] ### Step 4: Calculate the sum of pKa values Calculate the sum: \[ 2.34 + 9.60 = 11.94 \] ### Step 5: Divide by 2 to find pI Now divide the sum by 2: \[ \text{pI} = \frac{11.94}{2} = 5.97 \] ### Final Answer Thus, the isoelectric point (pI) of glycine is **5.97**. ---
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