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If the ionic product of Ni (OH)2 is 1.9x...

If the ionic product of Ni `(OH)_2` is `1.9xx10^(-15)`, the molar solubility of `Ni (OH)_2` in 1.0 M NaOH is

A

`3.2xx10^(-12)`

B

`2.0xx10^(-13)`

C

`4.34xx10^(-12)`

D

`0.58xx10^(-4)`

Text Solution

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The correct Answer is:
B
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