`CH_3-CH = CH_2+NOCl rarrP`, Identify the adduct.

Options

A. `CH_3-underset(Cl)underset(|)(CH)-underset(NO)underset(|)(CH_2)`
B. `CH_3-underset(NO)underset(|)(CH)-underset(Cl)underset(|)(CH_2)`
C. `CH_3-CH_2-underset(Cl)underset(|)overset(NO)overset(|)(CH)`
D. `underset(Cl)underset(|)(CH_2)-CH_2-underset(NO)underset(|)(CH_2)`

Answer

To identify the adduct formed from the reaction of propene (CH₃-CH=CH₂) with nitrosyl chloride (NOCl), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We have propene (CH₃-CH=CH₂), which is an alkene, and nitrosyl chloride (NOCl).

2. **Understand the Electrophile and Nucleophile**:
- In this reaction, NOCl acts as an electrophile. It can dissociate into NO⁺ (nitrosonium ion) and Cl⁻ (chloride ion). The NO⁺ ion is the active electrophile that will react with the alkene.

3. **Electrophilic Addition Mechanism**:
- The double bond in propene (C=C) acts as a nucleophile and will attack the nitrosonium ion (NO⁺). This results in the formation of a carbocation.

4. **Carbocation Stability**:
- When the double bond attacks the NO⁺, a carbocation is formed. The stability of the carbocation will determine which carbon atom the NO⁺ will attach to. In this case, the carbocation will form on the more stable carbon, which is the one adjacent to the CH₃ group (the secondary carbocation).

5. **Formation of the Adduct**:
- The structure of the carbocation will be CH₃-CH⁺-CH₂-NO. The NO will then bond to the carbon that has the positive charge, leading to the formation of the product.

6. **Final Product**:
- The final product (adduct) will be CH₃-CH(NO)-CH₂Cl, where the NO group is attached to the second carbon of the original propene structure.

### Final Answer:
The adduct formed from the reaction of propene with NOCl is **CH₃-CH(NO)-CH₂Cl**.