Consider the following sequence of reaction. Identify the final product (Y) `CH_3CH_2CH_3overset(Cl_2//hv)rarr(X)overset(aq.OH^(-))rarr(Y)`

Options

A. propan -1 -ol
B. propan -2- ol
C. mixture of both propan -1-ol and propan - 2 - ol
D. ethanol

Answer

To solve the problem, we need to analyze the given sequence of reactions step by step.

1. **Identify the starting compound**: The starting compound is propane, which is represented as \( CH_3CH_2CH_3 \).

2. **First reaction with \( Cl_2 \) in the presence of light**: This reaction indicates a free radical halogenation process, specifically monochlorination. In this process, chlorine (\( Cl_2 \)) will react with propane under UV light to form a chlorinated product. The two possible products from this reaction are:
- \( CH_3CH_2CH_2Cl \) (1-chloropropane)
- \( CH_3CHClCH_3 \) (2-chloropropane)

Given that the reaction favors the formation of the more stable radical, 2-chloropropane (\( CH_3CHClCH_3 \)) will be the major product (let's denote this as \( X \)).

3. **Second reaction with aqueous \( OH^- \)**: The next step involves treating the chlorinated product \( X \) with aqueous hydroxide ions (\( OH^- \)). This is a nucleophilic substitution reaction (S_N2 mechanism), where the hydroxide ion will attack the carbon atom bonded to the chlorine atom and displace the chlorine atom.

- If we take \( X \) as 2-chloropropane (\( CH_3CHClCH_3 \)), the hydroxide ion will attack the carbon that has the chlorine, leading to the formation of 2-propanol (\( CH_3CHOHCH_3 \)).
- If we take \( X \) as 1-chloropropane (\( CH_3CH_2CH_2Cl \)), the hydroxide ion will attack the terminal carbon, leading to the formation of 1-propanol (\( CH_3CH_2CH_2OH \)).

4. **Final product \( Y \)**: Since both products can be formed depending on the initial chlorination product, the final product \( Y \) can either be 1-propanol or 2-propanol. However, since 2-chloropropane is the major product from the first step, the final product \( Y \) is predominantly 2-propanol.

Thus, the final product \( Y \) is **2-propanol**.

### Summary of Steps:
1. Start with propane (\( CH_3CH_2CH_3 \)).
2. React with \( Cl_2 \) in light to form 2-chloropropane (\( CH_3CHClCH_3 \)) as the major product \( X \).
3. React \( X \) with aqueous \( OH^- \) to produce 2-propanol (\( CH_3CHOHCH_3 \)) as the final product \( Y \).