sin[cot^(1){tan(cos^(-1)x)}]" is equal to "

If x gt 0 , then the value of sin[cot^(-1)cos(tan^(-1)x)] is equal to -

If x gt 0 , then the value of sin[cot^(-1)cos(tan^(-1)x)] is equal to -

cos[tan^(-1){sin(cot^(-1)x)}] is equal to

sin[cot^(-1){cos(tan^(-1)x)}]=

If x gt 0 then the value of sin [cot ^(-1) cos( tan^(-1)x)] is equal to-

Find the value of sin[cot^(-1){tan(cos^(-1)x)}]

The value of 2tan^(-1)(cos ec tan^(-1)x-tan cot^(-1)x) is equal to (a)cot ^(-1)x( b ) (cot^(-1)1)/(x) (c)tan ^(-1)x (d) none of these

The value of sin[cot^(-1){cos(tan^(-1) x)}] is

The value of sin[cot^(-1){cos(tan^(-1) x)}] is

The value of sin [cot^(-1) {cos (tan^(-1)x)}] is :