f(1)=1,n>=1rArr f(n+1)=2,f(n)+1" then "f(n)

f(1)=1, n ge 1 f(n+1)=2f(n)+1 then f(n)=

If f(1)=1, f(n+1)=2f(n)+1, n ge1 , then f(n) is

If f(1)=1 and f(n+1)=2 f(n)+1 , then f(n) is

If f(1) = 1, f(n+1)= 2f (n) + 1, n ge 1 then f(n) = .........

f (1) = 1, n> = 1f (n + 1) = 2f (n) +1 then f (n) =

If f(1) = 1 and f(n + 1) = 2 f(n) + 1, if n ge 1, then f(n) is.

If f(x+1)+f(x-1)=2f(x)a n df(0),=0, then f(n),n in N , is nf(1) (b) {f(1)}^n (c) 0 (d) none of these

If f(x+1)+f(x-1)=2f(x)a n df(0),=0, then f(n),n in N , is nf(1) (b) {f(1)}^n (c) 0 (d) none of these

f:N to R is given by f(1)=1 and f(1)+2f(2)+3f(3)+……+nf(n)=n(n+1) f(n) , for n ge 2 , then f(1994)=

Let f:N rarr R be a function such that (ii) f(1)+2f(2)+3f(3)+.........+nf(n)=n(n+1)f(n)=n(n+1)f(n)AA n>=2 Then find f(2011)