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If f(x+1)+f(x-1)=2f(x)a n df(0),=0, then...

If `f(x+1)+f(x-1)=2f(x)a n df(0),=0,` then `f(n),n in N ,` is
(a)`nf(1)`
(b) `{f(1)}^n`
(c)`0`
(d) none of these

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