`3q-5=7`

-p+[8q-{5p-(3q-7r-3-r^(2))}]

If 10! =2^(p).3^(q).5^(r).7^(s) , then -

if 10!=2^(p)3^(q)5^(r)7^(s) then

(10!)=(2)^p.(3)^q.(5)^r.(7)^8 then

If 2p+3q+4r=15, the maximum value of p^(3)q^(5)r^(7) will be

IF P:Q=3/5:5/7, Q:R=3/4:2/5 then what is P:Q:R equal to

Discussion Excercise 1 ( Q 3,5,6,7)|| Excercise 4 level 1 ( Q 1 to Q 5)

Let A={1,3,5,7} and B={p,q,r} .Let R be a relation define by R={(1,p),(3,r),(5,q),(7,p),(7,q)} , find the domain and range of R .

Expand the following using binomial theorem. ((2p)/(5)-(3q)/(7))^(6)

Expand the following using binomial theorem. ((2p)/(5)-(3q)/(7))^(6)