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If cos x+cos y+cosz=0=sinx+siny+sinz the...

If `cos x+cos y+cosz=0=sinx+siny+sinz` then `tan(x-y)=`

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Knowledge Check

  • If cos x + cos y + cos z =0 = sin + sin y +sin z then tan (x-y) =

    A
    `sqrt3`
    B
    `-sqrt3`
    C
    `(1)/(sqrt3)`
    D
    `-(1)/(sqrt3)`

  • If cosx+cosy+cosz=sinx+siny+sinz=0" then "cos(x-y)=

    A
    0
    B
    `-(1)/(2)`
    C
    2
    D
    1

  • If cos x +cosy+cosalpha=0 , sinx+siny+sinalpha=0 then cot((x+y)/2)=

    A
    `sinalpha`
    B
    `cos alpha`
    C
    `tan alpha`
    D
    `cot alpha`

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    If cosx + cosy + cosz = 0 = sinx + siny + sinz ,then possible value of cos((x-y)/2) is (A) 4 3 1 2 (B) 4 3 2 1 (C) 3 4 2 1 (D) 3 4 1 2

    If cosx+cosy+cosz=0 and sinx+siny+sinz=0 then show that cos(x-y)+cos(y-z)+cos(z-x)=-3/2

    If cos x+ cos y=asin x+siny=b then prove that tan(x+y)=(2ab)/(a^(2)-b^(2))

    If cosx + cosy + cosz = 0 and sinx + siny + sinz =0 , then show that cos (x-y) + cos(y - z) + cos(z - x) = - 3/2.

    If cosx + cosy + cosz = 0 "and" sinx + siny + sinz =0, "then show that" cos (x-y) + cos(y - z) + cos(z - x) = - 3/2.

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