When an oxide `M_(2)O_(3)` is oxidised to `M_(2)O_(5)` its equivalent is

H_(2)O is oxidised to O_(2) by :

2Mn_(2)O_(7)rarr4MnO_(2)+3O_(2) ( if M is m ol.wt. of Mn_(2)O_(7) ). Find the equivalent weight of Mn_(2)O_(7) in above change.

VA group elements form tri oxides and pentoxides of the type M_(2)O_(3) and M_(2)O_(5) respectively (M-VA group element). The trioxides and pentoxides of nitrogen are monomers and that of P,As,Sb are dimers. Nitrogen forms various oxides ranging from NO to N_(2)O_(5) . Oxides of phosphorous have cage like stuctures. Number of P-O-P bonds in P_(4)O_(10) :

When 0.1 mole Cr_(2)O_(7)^(-2) is oxidised then quantity of elecricity required to completely oxidise Cr_(2)O_(7_^(-2)) to Cr^(+3) is :-