`" The substitution required to change "(3y-7x+7)dx+(7y-3x+3)dy=0" to a homogeneous D.E is "`

(3x-7y-3)dy=(3y-7x+7)dx

The solution of e^(2x-3y)dx+e^(2y-3x)dy=0 is

The differential equation (dy)/(dx)=(7x-3y-7)/(-3x+7y+3) reduces to homogeneous form by making the substitution

Find the product of (3x+7y) and (3x-7y)

Identify the statement(s) which is/are true. (a) f( x , y )= e^( y/ x )+tan y/ x is a homogeneous of degree zero. (b) xln y/ x dx+ y^(2)/ x *sin^-1(y/ x ) dy=0 is a homogeneous differential equation. (c)f( x ,y )= x^(2)+sinx cosy is a non homogeneous. (d)( x^(2)+ y^(2))dx-(x y^(2)-y^(3))dy=0 is a homogeneous differential equation.

(dy)/(dx)=(3y-x+7)/(x-7y-3)

x+7y=10 3x-2y=7

7x - 2y = 3 , 22x - 3y = 16 .

Add -7x y ,\ -3x y and -9x ydot

Solve for x and y, using substitution method : 2x + y = 7, 4x - 3y + 1 =0