Find the value of `2^n{1. 3 .5.....(2n-3)(2n-1)}`

(i) If (n!)/(2.(n-2)!): (n!)/(4!.(n-4)!) = 2:1 , find the valye of n. (ii) If ((2n)!)/(3!(2n-3)!): (n!)/(2!(n-2)!) = 44:3 , then find the value of n.

Find the value of n if 2n+1,n^(2)+n+1,3n^(2)-3n+3 are consecutive terms of an AP

Find the value of (3^(n)xx3^(2n+1))/(9^(n)xx3^(n-1)) .

If H_(n)=1+(1)/(2)+(1)/(3)+...+(1)/(n), then value of 1+(3)/(2)+(5)/(3)+...+(2n-1)/(n) is

Find the value of the products: (3m-2n)(2m-3n) at m=1,n=-1

Find the value of ( 1 - 1/3 ) ( 1 - 1/4 ) ( 1 - 1/5 ) ---------- ( 1 - 1/n ) is ( a ) 2/n ( b ) 4/n ( c ) 3/n ( d ) 5/n