If the focus and directrix of a parabola are `(3,-4)` and `x+y+7=0` then its length of latusrectum is

The focus and directrix of a parabola are (1,-1) and x+y+3=0. Its vertex is

If focus and directrix of a parabola are (3,5) and x+y=4, then coordinates of its vertex are

Find the focus and directrix of the parabola 3x^2 + 12x + 8y=0 .

If the focus of a parabola is (3,3) and its directrix is 3x-4y=2 then the length of its latus rectum is

The focus and directrix of a parabola are (1,2) and 2x-3y+1=0 .Then the equation of the tangent at the vertex is

The focus and directrix of a parabola are (1,2) and 2x-3y+1=0 .Then the equation of the tangent at the vertex is

the focus and directrix of a parabola are (1 2) and 2x-3y+1=0 .Then the equation of the tangent at the vertex is

The focus and directrix of a parabola are (1 2) and 2x-3y+1=0 .Then the equation of the tangent at the vertex is

The focus and directrix of a parabola are (1 2) and 2x-3y+1=0 .Then the equation of the tangent at the vertex is

The focus and directrix of a parabola are (1 2) and 2x-3y+1=0 .Then the equation of the tangent at the vertex is