Solve `(-sin theta)/(1-cos theta)`

Solve ((1-sin theta)/(cos theta))

1- (sin ^ (2) theta) / (1 + cos theta) + (1 + cos theta) / (sin theta) - (sin theta) / (1-cos theta) - (1) / (sec theta)

1-(sin^(2)theta)/(1+cos theta)+(1+cos theta)/(sin theta)-(sin theta)/(1-cos theta) equals

(sin theta)/(1+cos theta) is equal to (1+cos theta)/(sin theta)(b)(1-cos theta)/(cos theta)(c)(1-cos theta)/(sin theta) (d) (1-sin theta)/(cos theta)

(cos^(2)theta(1-cos theta))/(sin^(2)theta(1-sin theta))=(1+sin theta)/(1+cos theta)

Solve sin^(2) theta-cos theta=1/4, 0 le theta le 2pi .

Solve sin^2 theta- cos theta =1/4 " for " theta and write the value of theta in the interval 0 le theta le 2 pi

Solve (3 sin theta-sin 3 theta)/(sin theta)+(cos 3 theta)/(cos theta)=1 .

Prove (cos theta)/(1-sin theta)=(1+cos theta+sin theta)/(1+cos theta-sin theta)