Equation of standing waves in a string under tension T=10N is given by `Y=2sin(10 pi x)sin(100 pi t)`cm where x is in m and t is in second). Linear mass density of string is

Equation of standing waves in a string under tension T=10N is given by , Y=2sin(10 pi x)sin(100 pi t)cm x is in m and t is in second).Linear mass density of string is

The equation of standing wave in a stretched string is given by {y =2sin [pi /2 (x)] cos(20 pi t)} where x and y are in meter and t is in second. Then minimum separation between two particle which are at the antinodes and having same phase will be

A standing wave on a string is given by y = ( 4 cm) cos [ x pi] sin [ 50 pi t] , where x is in metres and t is in seconds. The velocity of the string section at x = 1//3 m at t = 1//5 s , is

The transverse displacement of a string fixed at both ends is given by y=0.06sin((2pix)/(3))cos(100pit) where x and y are in metres and t is in seconds. The length of the string is 1.5 m and its mass is 3.0xx10^(-2)kg . What is the tension in the string?

The equation of a transverse wave propagating in a string is given by y = 0.02 sin (x + 30t) where, x and y are in second. If linear density of the string is 1.3 xx 10^(-4)kg//m , then the tension in the string is

The equation of stationary wave along a stretched string is given by y=5 sin (pix)/(3) cos 40 pi t , where x and y are in cm and t in second. The separation between two adjacent nodes is

The equation of a transverse wave propagating in a string is y=0.02sin(x-30t) . Hwere x and y are in metre and t is in second. If linear density of the string is 1.3xx10^(-4)kg//m , then the tension in the string is :