Molarity of 1m aqueous NaOH solution [density of the solution is 1.02 g/ml]

The molarity of NaNO_(3) solution is 1 M. The density of solution is 1.25 g/ml. Calculate molality of solution. (Molar-Mass of NaNO_(3)=85 g ).

The mole fraction of NaOH in its aqueous solution is 0.2 and density of this solution is 1.12 gm/ml then molarity of the solution is -

Calculate Molarity of 40% NaOH (w/W). The density of solution is 1.2 g/ml.

M = molarity of the solution m = molality of the solution d = density of the solution (in g. ml^(-1) ) M^(-1)= gram molecular weight of solute Which of the following relations is correct

A solution of glucose ("molar mass"= 180g mol^(-1)) in water is labelled as 10% (by mass). What would be the molarity and molality of the solution? Given that the density of the solution is 1.2g mL^(-1) .

An aqueous solution of glucose is labelled as 0.05 m . Which of the following options correctly respresent the concentration of the solution if density of solution is 1.009 g//mL is :