Number of milli equivalents of solute in 0.5 litres of 0.2 N solution is

Number of gram equivalents of solute in 100 ml of 5N HCl solution is

Number of milli equivalents of solute present in 250 ml of 0.1 M oxalic acid solution are

The number of milli equivalent in 100 ml of 0.5 N HCl solution is

Calculate the number of equivalents in 10 litre of 0.5 Mba(OH)_(2) solution (Ba = 137)

A: Solution containing 1 gram equivalent of solute per litre is known as 1N solution R: N=M times n -factor

Calculate the number of moles of methanol in 5 litres of its 2 m solution if the density of solution is 0.981 kg (Molar mass of methanol=32.0g mol^(-1) .