(dy)/(dx)=sin(x+y)+cos(x+y)

The solution of differential equation 2y sin x(dy)/(dx)=sin2x-y^(2)cos x ,satisfying y((pi)/(2))=1 is

If y=y(x) is the solution of the equation e^(sin y) cos y""(dy)/(dx) +e^(sin y) cos x = cos x,y (0)=0, then 1+y ((pi)/(6)) +( sqrt(3))/(2) y((pi)/(3)) +(1)/( sqrt(2)) y((pi)/(4)) is equal to

cos y (dy) / (dx) + sin y cos x = sin x cos x

Solve (dy)/(dx)=cos(x+y)-sin(x+y) .

Solve (dy)/(dx)=cos(x+y)-sin(x+y) .

Solve (dy)/(dx)=cos(x+y)-sin(x+y) .

(dy)/(dx)=(x+sin x)/(y+cos y)

Find the particular solution of the differential equation. (dy)/(dx) = ((x sin((x)/(y))-y cos ((x)/(y)))y)/((y cos ((x)/(y))+x sin ((x)/(y)))x) , given that y = 1 when x = (pi)/(4)

Find the particular solution of the differential equation. (dy)/(dx) = ((x sin((x)/(y))-y cos ((x)/(y)))y)/((y cos ((x)/(y))+x sin ((x)/(y)))x) , given that y = 1 when x = (pi)/(4)