[tan^(-1)(x^(2)+y^(2))=a],[(dy)/(dx)=?]

If tan^(-1)(x^(2)+y^(2))=alpha then (dy)/(dx) is equal to

If x = e^(tan^(-1))((y-x^2)/x^2) then (dy)/(dx)=

If tan^-1(x^2+y^2)=alpha,then(dy)/(dx) is equal to

If tan^-1(x^2+y^2)=alpha,then(dy)/(dx) is equal to

Solve the following differential equations (i) (1+x^(2)) (dy)/(dx) + y = e^(tan^(-1))x (ii) (1+x^(2))(dy)/(dx) + y = tan^(-1)x

If x = e^(tan^(-1)((y-x^(2))/x^(2)) then dy/dx =

If tan ^(-1)((x^(2)-y^(2))/(x^(2)+y^(2)))=a, prove that (dy)/(dx)=(x)/(y)((1-tan a))/((1+tan a))

If x+y= tan^(-1)y and (d^(2)y)/(dx^(2))=f(y)(dy)/(dx) then f(y)=

If tan^(-1)((y)/(x))-(1)/(2)log_(a)(x^(2)+y^(2))=0, then (dy)/(dx) is