" (d) "(4)/(9)a^(2)+b^(2)+(4)/(3)ab

Multiply : -(2)/(3)a^(7)b^(2) and -(9)/(4)ab^(5)

The factors of 8a^(3)+b^(3)-6ab+1 are (a) (2a+b-1)(4a^(2)+b^(2)+1-3ab-2a) (b) (2a-b+1)(4a^(2)+b^(2)-4ab+1-2a+b)(2a+b+1)(4a^(2)+b^(2)+1-2ab-b-2a) (d) (2a-1+b)(4a^(2)+1-4a-b-2ab)

If (2)/(2+(2)/(2+(2)/(x)))=3, then x is equal to -(4)/(7) (b) (4)/(7)(c)-(4)/(9)(d)(4)/(9)

Simplify ((7)/(9)a - (4)/(3) b) ^(2) -ab

What is the HCF of a^(2)b^(4)+2a^(2)b^(2) and (ab)^(7)-4a^(2)b^(9) ?

Simplify : (2a+3b+4c) ( 4a^(2) + 9b^(2) + 16c^(2) -6ab - 12bc - 8ca )

a^(2)b^(3)x2ab^(2) is equal to: 2a^(3)b^(4)(b)2a^(3)b^(5)(c)2ab (d) a^(3)b^(5)

If a+b+c=0 and a^(2)+b^(2)+c^(2)=1, then (a) ab+bc+ca=(1)/(2)( b) ab+bc+ca=(1)/(2)( c) a^(4)+b^(2)+c^(4)=(1)/(2)( d) a^(4)+b^(4)+c^(4)=(3)/(2)