[2y cos n=tan y,cot y=tan2],[cot2=tan n tan sin n=]

If cos x=tan y,cot y=tan z and cot z=tan x, then sin x=

If cos x= tan y , coty= tan z , cot z= tan x then sin x=

If cos x = tan y , cot y= tan z and cot z= tan x, then sin x =

If cos x = tan y, cot y = tan z and cot z = tan x, then sin x =

If tan(cot x) = cot (tan x) , then sin 2x =

Solution of the differential equation dy/dx+(1+cos 2y)/(1-cos 2x)=0 is a) tan y+cot x=c b) tan y-cot x=c c) tan y.cot x=c d) cot y.tan x=c

If tan (cot x) = cot (tan x) , prove that : sin 2x = 4/((2n+1) pi)

If tan(cot x)=cot(tan x), prove that :sin2x=(4)/((2n+1)pi)