The solution `y^(n-1)(ay'+y)=x` is

The solution of y'-y=1, y(0) =1 is given by y(x) =

The solution of y'-y=1,y(0)=-1 is given by y(x)=

The solution of (x^(2)-ay)dx=(ax-y^(2))dy is

The solution of y'-y = 1 , y(0)=1 is given by y(x) =

The solution set of x-ay=4 and x+y=0 is (1,-1) the value of a is …………..

If f(x+y)=f(x)+f(y)-xy-1 AA x, y in R and f(1)=1 then the number of solution of f(n)=n, n in N is

int (1)/(y (1-ay)) dy

If the system of equations, a^(2) x - ay = 1 - a and bx + (3-2b) y = 3 + a possess a unique solution x = 1 , y = 1 , then