" (ii) "4x+3y-4=0;6x=8-5y

Solve the following simultaneous equations using Cramer's rule. 4x+3y-4=0,6x=8-5y .

Solve the simultaneous equations using Cramer's rule 4x+3y-4=0, 6x = 8 -5y

4x+3y=4,6x+5y=8

Prove that the point (2,2) is equidistant from the three straight lines 4x+3y-4=0,12x-5y+12=0and3x-4y=8.

Solve the following simultaneous equations using Cramer’s rule. 4x + 3y - 4 = 0 , 6x = 8 - 5y

Show that the point (-8,3) is equidistant from the straight lines 4x-3y+1=0and12x-5y+7=0 .

4x-3y=8, 6x-y=29/3

2x+3y=8 4x-5y=-6

Equation of the line equidistant from 3x+4y-25=0 and 3x+4y+25=0 is (A) 6x+4y+5=0 (B) 3x+4y=0 (C) 3x-4y+5=0 (D) 6x+8y+5=0