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~ ( p hArr q) is-...

` ~ ( p hArr q)` is-

A

`~ p ^^ ~ q`

B

`~ p vv ~ q`

C

`~ p ^^ ~ q`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine the expression \( \sim (p \leftrightarrow q) \), we will construct a truth table and analyze the logical equivalences step by step. ### Step 1: Define the Variables We have two variables, \( p \) and \( q \). They can take values of either True (T) or False (F). ### Step 2: Create the Truth Table We will create a truth table for \( p \) and \( q \): | \( p \) | \( q \) | |---------|---------| | T | T | | T | F | | F | T | | F | F | ### Step 3: Calculate \( p \leftrightarrow q \) The biconditional \( p \leftrightarrow q \) is true if both \( p \) and \( q \) have the same truth value. We can fill this in the truth table: | \( p \) | \( q \) | \( p \leftrightarrow q \) | |---------|---------|----------------------------| | T | T | T | | T | F | F | | F | T | F | | F | F | T | ### Step 4: Negate \( p \leftrightarrow q \) Now we need to find \( \sim (p \leftrightarrow q) \). This means we will negate the values in the column for \( p \leftrightarrow q \): | \( p \) | \( q \) | \( p \leftrightarrow q \) | \( \sim (p \leftrightarrow q) \) | |---------|---------|----------------------------|-----------------------------------| | T | T | T | F | | T | F | F | T | | F | T | F | T | | F | F | T | F | ### Step 5: Final Result The final column \( \sim (p \leftrightarrow q) \) gives us the truth values for the negation of the biconditional. The results are: - For \( (T, T) \): F - For \( (T, F) \): T - For \( (F, T) \): T - For \( (F, F) \): F Thus, \( \sim (p \leftrightarrow q) \) is equivalent to the expression that is true when \( p \) and \( q \) have different truth values (i.e., it is equivalent to \( p \oplus q \), the exclusive OR).
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