The equation of the circumcircle of an equilateral triangle is `x^2+y^2+2gx+2fy+c=0` and one vertex of the triangle in (1, 1). The equation of the incircle of the triangle is `4(x^2+y^2)=g^2+f^2` `4(x^2+y^2)=8gx+8fy=(1-g)(1+3g)+(1-f)(1+3f)` `4(x^2+y^2)=8gx+8fy=g^2+f^2` `non eoft h e s e`

Options

A. `4(x^2+y^2)=g^2+1^2`
B. `4(x^2+y^2)+8gx+8fy=(1-g)(1+3g)+(1-f)(1+3f)`
C. `4(x^2+y^2)+8gx+8fy=g^2+f^2`
D. none of these

Answer

B