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An isosceles triangle A B C is inscribed...

An isosceles triangle `A B C` is inscribed in a circle `x^2+y^2=a^2` with the vertex `A` at `(a ,0)` and the base angle `Ba n dC` each equal `75^0` . Then the coordinates of an endpoint of the base are. `(-(sqrt(3a))/2, a/2)` (b) `(-(sqrt(3a))/2, a)` `(a/2,(sqrt(3a))/2)` (d) `((sqrt(3a))/2,-a/2)`

A

`((asqrt3)/2,a/2)`

B

`(-(asqrt3)/2,a/2)`

C

`((asqrt3)/2,-a/2)`

D

`(-(asqrt3)/2,-a/2)`

Text Solution

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The correct Answer is:
B, D
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