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Let T be the triangle with vertices (0,0...

Let T be the triangle with vertices `(0,0), (0,c^2 )and (c, c^2)` and let R be the region between `y=cx and y = x^2` where `c > 0` then

A

area `(R ) = (C^(3))/(6)`

B

area `(R ) = (C^(3))/(3)`

C

`underset(c to oo)(lim) (area)/(area) ((T))/((R )) = 3`

D

`underset(c to oo)(lim) (area)/(area) ((T))/((R )) = (3)/(2)`

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The correct Answer is:
A,C
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