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A dictionary compriing of four lettered ...

A dictionary compriing of four lettered words is formed by arranging individually the letters of the words SLOW and FAST. What is rank of the word SLOW?

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To find the rank of the word "SLOW" in a dictionary formed by the arrangements of the letters of the words "SLOW" and "FAST", we will follow these steps: ### Step 1: List the Letters The letters in "SLOW" are S, L, O, and W. ### Step 2: Arrange the Letters in Alphabetical Order We need to arrange the letters in alphabetical order: - The alphabetical order of the letters is: **L, O, S, W**. ### Step 3: Count Words Before "SLOW" To find the rank of "SLOW", we need to count how many words would come before it in a dictionary. 1. **Words starting with L**: - Remaining letters: O, S, W - The number of arrangements = 3! = 6 2. **Words starting with O**: - Remaining letters: L, S, W - The number of arrangements = 3! = 6 3. **Words starting with S**: - Now we fix S and look at the next letter. - Remaining letters: L, O, W ### Step 4: Count Words Starting with SL 1. **Words starting with SL**: - Remaining letters: O, W - The number of arrangements = 2! = 2 ### Step 5: Count Words Starting with SO 1. **Words starting with SO**: - Remaining letters: L, W - The number of arrangements = 2! = 2 ### Step 6: Count Words Starting with SW 1. **Words starting with SW**: - Remaining letters: L, O - The number of arrangements = 2! = 2 ### Step 7: Total Count of Words Before "SLOW" Now, we sum all the counts: - Words starting with L: 6 - Words starting with O: 6 - Words starting with SL: 2 - Words starting with SO: 2 - Words starting with SW: 0 (since SLOW is the next arrangement) Total words before "SLOW" = 6 + 6 + 2 + 2 = 16 ### Step 8: Calculate the Rank The rank of "SLOW" is the total number of words before it plus 1 (to include "SLOW" itself): - Rank of "SLOW" = 16 + 1 = 17 ### Final Answer The rank of the word "SLOW" is **17**. ---
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