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Four men and six women are to be seated ...

Four men and six women are to be seated along a round table. The number of cases where every two men are separated by to women is

A

3420

B

43200

C

1710

D

None of these

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The correct Answer is:
To solve the problem of seating 4 men and 6 women around a round table such that no two men sit next to each other, we can follow these steps: ### Step 1: Arrange the Women First, we need to arrange the 6 women around the round table. The number of ways to arrange \( n \) people around a round table is given by \( (n-1)! \). Therefore, for 6 women, the number of arrangements is: \[ (6-1)! = 5! = 120 \] **Hint:** Remember that in circular permutations, we fix one person to eliminate identical arrangements due to rotation. ### Step 2: Identify Spaces for Men Once the women are seated, we can visualize the arrangement. With 6 women seated, there will be 6 gaps (spaces) between them where the men can be seated. This can be represented as: - W1 _ W2 _ W3 _ W4 _ W5 _ W6 _ Here, each underscore (_) represents a gap where a man can be seated. **Hint:** Count the gaps created by the arrangement of women; these are the only places where men can sit. ### Step 3: Choose Spaces for Men We need to choose 4 out of the 6 available gaps to place the men. The number of ways to choose 4 gaps from 6 is given by the combination formula \( \binom{n}{r} \): \[ \binom{6}{4} = \binom{6}{2} = 15 \] **Hint:** Use the combination formula to select spaces where the men will sit, ensuring that they are separated by women. ### Step 4: Arrange the Men After selecting the gaps, we need to arrange the 4 men in the chosen gaps. The number of ways to arrange 4 men is given by \( 4! \): \[ 4! = 24 \] **Hint:** Remember that the arrangement of distinct individuals (men) is calculated using factorial. ### Step 5: Calculate Total Arrangements Now, we can find the total number of arrangements by multiplying the arrangements of women, the selection of gaps, and the arrangements of men: \[ \text{Total arrangements} = \text{(Arrangements of Women)} \times \text{(Ways to choose gaps)} \times \text{(Arrangements of Men)} \] Substituting the values we calculated: \[ \text{Total arrangements} = 5! \times \binom{6}{4} \times 4! = 120 \times 15 \times 24 \] ### Step 6: Perform the Calculation Now we compute the total: \[ 120 \times 15 = 1800 \] \[ 1800 \times 24 = 43200 \] Thus, the total number of arrangements where every two men are separated by women is: \[ \boxed{43200} \]
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