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Let A={x(1),x(2),x(3)....,x(7)},B={y(1)y...

Let `A={x_(1),x_(2),x_(3)....,x_(7)},B={y_(1)y_(2)y_(3)}`. The total number of functions `f:AtoB` that are onto and ther are exactly three elements x in A such that `f(x)=y_(2)`, is equal to

A

`14.^(7)C_(2)`

B

`14.^(7)C_(3)`

C

`7.^(7)C_(2)`

D

`7.^(7)C_(3)`

Text Solution

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The correct Answer is:
b
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