" Q) "f(x)={[x^(2)+3x+p;" for "x<=1],[" vret "2" ,for "x>1]

Find the values of p and q, so that f(x) = {(x^(2) + 3x + p,x le 1),(qx + 2,x gt 1):} is differentiable at x=1.

If the function f (x) defined below is differentiable at x = 1 then find the values of p and q . f(x)={{:(x^(2)+3x+p",","when "xle1),(qx+3",","when "xgt1):}

Find the values of p and q , so that f(x)={{:(x^(2)+3x+p, ifxle1),(qx+2,ifx gt1):} is differentiable at x = 1

Find the values of p and q , so that f(x)={{:(x^(2)+3x+p, ifxle1),(qx+2,ifx gt1):} is differentiable at x = 1

The sum of the polynomials p(x) = x^(3) - x^(2) - 2, q(x) = x^(2) - 3x + 1

If P (x) = (x^(3) + 1) (x-1) and Q (x) = (x^(2) -x +1) (x^(2) -3x +2) , then find HCF of P (x) and Q (x) .

If f(x) = {:{(px^(2)-q, x in [0,1)), ( x+1 , x in (1,2]):} and f(1) =2 , then the value of the pair ( p,q) for which f(x) cannot be continuous at x =1 is:

If f(x) = {:{(px^(2)-q, x in [0,1)), ( x+1 , x in (1,2]):} and f(1) =2 , then the value of the pair ( p,q) for which f(x) cannot be contiinuous at x =1 is

If f(x) {:(=px-q", if " x le 1 ),(= 3x ", if " 1 lt x lt 2 ), (= qx^(2)-p ", if " x ge 2 ):} is continuous at x = 1 and dicontinuous at x = 2 , then