The number of values of `alpha` in `[0, 2pi]` for which `2 sin^3alpha-7sin^2 alpha + 7 sin alpha= 2` , is:

The number of values of alpha in [0,2pi] for whilch 2sin^(3)alpha-7sin^(2)alpha+7 sin alpha=2 , is

If (3 pi)/(4)

The value of alpha in [0,2pi] which does not satify the equation int_(pi//2)^(alpha) sin x dx = sin 2 alpha, is

The value of alpha in [0,2pi] which does not satify the equation int_(pi//2)^(alpha) sin x dx = sin 2 alpha, is

The value of alpha in (-pi, 0) satisfying sin alpha+int_(alpha)^(2alpha) cos2 x dx=0 , is

If alpha=(pi)/21 then (sin 3 alpha+sin 7 alpha)/(sin 24 alpha+sin 14 alpha)=

If alpha=(pi)/(21) then (sin3 alpha-sin7 alpha)/(sin24 alpha+sin14 alpha)=