A particle is thrown vertically upwards. If its velocity is half of the maximum height is `20 m//s`, then maximum height attained by it is

A particle is thrown vertically upwards its velocity at half of the height is 10 m/s then the maximum height attained by it is ( g= 10 m//s^2)

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10sqrt2m//s . The maximum height attained by it is

When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10sqrt2m//s . The maximum height attained by it is

A particle thrown vertically upwards has velocity 10 ms^(-1) at half of its height, then maximum height attained by it is :

A stone is projected vertically upwards.When it reaches half the maximum height,its velocity is 20m/s.What is the maximum height attained by the stone? (g=10m/s^(2)

A stone is thrown vertically upwards. When stone is at a height half of its maximum height, its speed is 10 ms^-1 , then the maximum height attained by the stone is ( g= 10 ms^(-2) )