Two particle `P` and `Q` describe `S.H.M.` of same amplitude a same frequency `f` along the same straight line .The maximum distance between the two particles is `asqrt(2)` The phase difference between the two particle is

Two particles P and Q describe S.H.M. of same amplitude a, same frequency f along the same straight line from the same mean position. The maximum distance between the two particles is a sqrt(2) , If the initial phase difference between the particles is (pi)/(N) then find N :

Two particles P and Q describe S.H.M. of same amplitue 'A' and frequency n along the same straight line. The resultant displacement amplitude of the two S.H.M.s is (A//sqrt(2)) . The initial phase difference between the two particles is nearly

Two particles A and B are describing SHM of same amplitude (a) and same frequency (f) along a common straight line. The mean positions of the two SHMs are also same but the particles have a constant phase difference between them. It is observed that during the course of motion the separation between A and B is always less than or equal to a. (a) Find the phase difference between the particles. (b) If distance between the two particles is plotted with time, with what frequency will the graph oscillate?

Two particles P and Q performs S.H.M. of same amplitude 'A' and frequency n along the same straight line the resultant S.H.M. have the amplitude sqrt(2) times amplitude of individual. The initial phase difference between two particles will be nearly.

Two particles execute SHMs of the same amplitude and frequency along the same straight line. They cross one another when going in opposite direction. What is the phase difference between them when their displacements are half of their amplitudes ?