A flexible chain of weight W hangs between two fixed points A and B at the same level. The inclination of the chain with the horizontal at the two points of support is `theta = 60^(@)`. What is the tension of the chain at the point P where inclination of chain with horizonrtal is `phi = 30^(@)`

A flexible chain of weight W hangs between two fixed points A and B at the same level. The inclination of the chain with the horizontal at the two points of support is theta . Calculated the tension of the chain at end points and also at the lower most point . [Hints : Consider equilibrium of each half of the chain. ]

A flexible chain of weight W hangs between two fixed points A and B at the same level. The inclination of the chain with the horizontal at the two points of support is theta . Calculated the tension of the chain at end points and also at the lower most point . [Hints : Consider equilibrium of each half of the chain. ]

A flexible chain of weight W hangs between two fixed points A and B at the same level. The inclination of the chain with the horizontal at the two points of support is theta . Calculated the tension of the chain at end points and also at the lower most point . [Hints : Consider equilibrium of each half of the chain. ]

A chain of mass 'm' is attached at two points A and B of two fixed walls as shown in the figure. The tension in the chain at A is

A chain of mass 'm' is attached at two points A and B of two fixed walls as shown in the Find the tension in the chain near the walls at point A and at the mid point C .

Two balls are projected from the same point in the direction inclined at 60^(@) and 30^(@) to the horizontal. If they attain the same height , what is the ratio of their velocities ? What is the ratio of their initial velocities if they have same horizontal range ?

A uniform chain of mass M = 4.8 kg hangs in vertical plane as shown in the fig. (a) Show that horizontal component of tension is same throughout the chain. (b) Find tension in the chain at point P where the chain makes an angle theta = 15^(@) with horizontal. (c) Find mass of segment AP of the chain. [Take g = 10 m//s^(2), "cos" 15^(@) = 0.96 , "sin"15^(@) = 0.25 ]