One root of `x^3+x^2-2x-1=0` lies between

Assertion (A): One root of x^(3)-2x^(2)-1=0 lies between 2 and 3 Reason (R): If f(x) is continuous function and f(a),f(b), have oppsite signs then atleast one (or) odd number of roots of f(x)=0 lies between a and b

one root of x^(3)3x^(2)+4x-1=0 lies between

One roots of x^(3) - 7x + 7 = 0 lies between

If one root of x^3 -6x^2 +3x +10 =0 is 2 then the remaining two roots are

If both roots of the equation x^2-2ax + a^2-1=0 lie between (-2,2) then a lies in the interval

If both roots of the equation x^2-2ax + a^2-1=0 lie between (-2,2) then a lies in the interval

If both roots of the equation x^2-2ax + a^2-1=0 lie between (-2,2) then a lies in the interval

If one root of 2x^(3)+3x^(2)-8x+3=0 is the double the other then the roots are

If both roots of the equation x^(2)-2ax+a^(2)-1=0 lie between (-2,2) then a lies in the interval

If one root of x^(2)-x+3 a=0 is double the root of x^(2)-x+a=0 then non-zero value of ' a ' is